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Re: progression problem
by Vaibhav Panchal - Thursday, 19 May 2016, 04:46 PM
  s=1/2+2^2/2^2+3^2/2^3+4^2/2^4+5^2/2^5+6^2/2^6.....

s/2 = 1/2+3/2^2+5/2^3+.......

s/4 = 1/2+2*((1/2)/(1-1/2)-1

s=4*3/2=6

ans= 6