Re: Permutation /Combination
Hi Mac 07 |
I hope you mean that there are four denominations available and you can use any number of coins of a particular denomination to make the total sum as 50 paise.
In that case it is easier to observe that number of 1 paisa coins must be multiple of 5. So let number of 1 paisa coins be 5a, 5paise be b, 10 paise be c and 25 paise be d.
Thus we have, 5a + 5b + 10c + 25d = 50
i.e. a + b + 2c + 5d = 10
It's easier to calculate now with smaller values. Just check by putting d = 0, 1 and 2 and the total cases come out to be: (1 + 3 + 5 + 7 + 9 + 11) + (2 + 4 + 6) + (1) = 49.