
Dear Rupali u have understood the question very well. but there is some implementation prob. look there are 4 vowels to be arranged in 2 places but mind u 2 are simillar, for this you will have to take two cases, firstly on A, E and I is taken and permuted in 2 places, which comes out to be P(3,2)=6 and secondly case when both A's are present (2!)/(2!)=1
so a total of seven cases 