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Re: algebra
by TG Team - Thursday, 28 August 2014, 03:39 PM
  Hi Rudrendra smile

You can rearrange the given equation to find the ratio (yn/yn-1) = (n2 + n - 6)/(n2 - n - 6) = (n + 3)(n - 2)/(n - 3)(n + 2) = {(n + 3)/(n + 2)}{(n - 2)/(n - 3)}

So y50 = [{53/52}{48/47}][{52/51}{47/46}].....[{7/6}{2/1}]*y3 = {(53*48)/(6*1)}*3 = 1272. smile

Kamal Lohia