
Hi Rudrendra
You can rearrange the given equation to find the ratio (y_{n}/y_{n1})_{ = }(n^{2} + n  6)/(n^{2}  n  6) = (n + 3)(n  2)/(n  3)(n + 2) = {(n + 3)/(n + 2)}{(n  2)/(n  3)}
So y_{50} = [{53/52}{48/47}][{52/51}{47/46}].....[{7/6}{2/1}]*y_{3} = {(53*48)/(6*1)}*3 = 1272.
Kamal Lohia_{ }
