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Re: algebra 400 ques doubts
by TG Team - Thursday, 4 September 2014, 12:42 PM
  Hi Soumya smile

It is given that f(k) = 1/k for some particular values of x = k.

So for those values of x = k, we have k*f(k) = 1 i.e. k*f(k) - 1 = 0

i.e. for some particular values of x, we get x*f(x) - 1 as zero. And this x*f(x) - 1 is also a polynomial of one higher degree than that of f(x). And the values of x at which this new polynomial becomes zero are its roots.

I hope it helps. smile

Kamal Lohia