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 | Re: number system |
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find out the factors of of 25200 which is 5*5*7*3*3*2*2*2*2 now if u have to get the divisor as 4n+3 means we should select the odd factors only by this we can eliminate the 2s now the numbers are 35,175,75,63,7,15,315,1575,3for n=0 hope it's right |
| Re: number system |
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The HCF of three natural numbers x, y and z is 13. If the sum of x, y and z is 117, then how many ordered triplets (x, y, z) exist? ANS..27 i did upto x+y+z=9..after this i can't proceed.pls help. |
 | Re: number system |
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after getting x+y+z =9 you have to find such three numbers which do not have common factor(all three). ie except 3,3,3 you can take any three values. If you remember from Permutation we can find the answer as C(11,2)-cases when any 1 or 2 variables are zero therefore the final answer is c(11,2)-3*9-1=55-27-1=27 this additional 1 is for the case 3,3,3 |
