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Numbers.
by dhwani bhatt - Thursday, 26 July 2012, 10:54 PM
  smile
1) Three wheels make 60 , 36 , 24 revolutions per minute. Each has a red spot on its rim, which is at the lowest position at time zero.The red spots will all at this position again after...???

2) The LCM of two numbers is 630 and their HCF is 9. If the sum of num is 156..Find the difference of number ..??

3)In an election contested by two parties , Party D secured 12% of total votes more than party R. If party R got 132000 votes , by how many votes did he lose the election..??
Re: Numbers.
by TG Team - Friday, 27 July 2012, 01:18 PM
 

Hi Dhwani smile

1. LCM(60/60, 60/36, 60/24) = 60/12 = 5s.

2. 9xy = 630 and 9(x + y) = 156, solve for x, y and get the answer. I think there is some problem with data as 156 is not multiple of 9.

3. It is assumed here that every body voted. So R got 44% and D 56% of total. Now 44% of total is 132000, so 1% of total is 3000 and 12% of total is 36000.

Re: Numbers.
by dhwani bhatt - Friday, 27 July 2012, 05:19 PM
  Yeah its 253 and not 156. !

One more doubt sir--??

4)When processing flower nectar into honeybees extract , a considerable amount of water gets reduced.How much flower nectar must be processed to yield 1 kg of honey , if nectar contains 50% water and the honey obtained from this nectar contains 15% water ?

5)- A clock is set right at 12 noon on monday. It loses 1/2% on the correct time in the first week but gains 1/4% on the true time during the second week.The time shown on monday after two weeks will be ?
Re: Numbers.
by Mohit Sharma - Saturday, 28 July 2012, 03:47 PM
  Hi diwani
I calculated the time will be 6 pm.
It will be sum of 1/2*24*7=84 and 5/4*24*7= 294
Let me knw if it is wrng.
Thanks,
Re: Numbers.
by Mohit Sharma - Saturday, 28 July 2012, 04:00 PM
  Hi diwani,
For 4th prob.
I guess the ans would be 1.7kg of necter will be needed.
Because 1 kg of honey contains 15% water=150gms
and remaining 850 honey.
and necter contains 50% of water.
THe amount of necter remains same so it wil be 850+850=1700 gms.
Correct me if i m wrng.
THanks,
Re: Numbers.
by dhwani bhatt - Saturday, 28 July 2012, 07:51 PM
  Hi Mohit smile

Answer to 5th question is 11:34:48

$)--I din get why you added 850+850 ??
Re: Numbers.
by TG Team - Monday, 30 July 2012, 08:48 PM
 

Hi Dhwani smile

4. Look for the honey quantity which is not changing as water is evporating. Now because of evaporation, honey quantity is not changing only its percentage composition is changing.

So we want to get 1kg of honey that contains 85% honey extract i.e. 850g.

So this 850g of honey extract which amounts to 85% of 1 kg honey should be 50% of total flower nectar, i.e. flower nectar must be 1700g i.e. 1.7kg.

 

5. If clock loses 1/2% time, that means it shows 1/2% less time or 99.5% of actual time and when it gains 1/4% time, it shows 1/4% more or 100.25 of original time.

So in two weeks i.e. 2*7*24*60*60 seconds, it has travelled 99.5% of 100.25% of 2*7*24*60*60 seconds.

I hope you can calculate further part easily. smile

Re: Numbers.
by dhwani bhatt - Tuesday, 31 July 2012, 02:06 PM
  Thank-you sir smile

Please help me with the following question ?
-->There are 25 horses each of which runs at constant speed different from other horses.Since the track has only 5 lanes , each race can have atmost 5 horses.
If you need to find out 3 fastest horses , what is the minimum number of races needed to identify them.?
Re: Numbers.
by Mohit Sharma - Tuesday, 31 July 2012, 04:55 PM
  Hi Dhwani,
According to me ans wil be 6. As to divide 25 into 5 tracks and the remaining one race among the winners of the 5 races.
Correct me if i m wrng.
Thanks,
Re: Numbers.
by dhwani bhatt - Tuesday, 31 July 2012, 05:02 PM
  Hi Mohit..

What if you choose the fastest 3 horses in the group of (1-5) from where you are selecting only one.

I solved it in this way , we will group the horses in five groups , after the completion of race of each of this group , we will select top 3 from each of the group . this in total we will be left with 1f horses.
Now how to proceed from here---!!
Re: Numbers.
by dhwani bhatt - Tuesday, 31 July 2012, 05:20 PM
  Hi Mohit..

What if you choose the fastest 3 horses in the group of (1-5) from where you are selecting only one.

I solved it in this way , we will group the horses in five groups , after the completion of race of each of this group , we will select top 3 from each of the group . this in total we will be left with 15 horses.
Now how to proceed from here---!!
Re: Numbers.
by Mohit Sharma - Tuesday, 31 July 2012, 05:32 PM
  Hi Dhwani,
There is no point in selecting the fastest three horses from every race. It is a case of fastest three horses among 25 horses.
Compare it with the real time scenario of 25 people out of which only 3 can be the winner. So the top three will come from the race where they were individually a winner.
What is the ans by the way?

Thanks,
Re: Numbers.
by dhwani bhatt - Tuesday, 31 July 2012, 07:23 PM
  Hi Mohit smile

Answer is 25.
Re: Numbers.
by TG Team - Wednesday, 1 August 2012, 09:28 AM
 

Hi Dhwani smile

7 races are sufficient.

In first five races, we get five top scorers of whom a horse is going to be topper which can be found out in 6th race.

Now as we want to find top three scorers, it depends on top three scorers of all the first five races. So we can eliminate bottom two of each i.e. 10 horses from the race.

Also who scored fourth and fifth place in sixth race, they along with their predecessors in their earlier races can be removed safely i.e. 6 more removed. Also who scored second and third in sixth race, we can remove one and two persons behind them in their earlier race respectively i.e. 3 more removed. The horse who topped sixth race is topper overall, so leave him also.

So finally we are left with 25 - 10 - 6 - 3 - 1 = 5 horses which can participate in seventh race and decide the second and third scorer of all the 25 horses.

Re: Numbers.
by Mohit Sharma - Wednesday, 1 August 2012, 11:59 AM
  hello sir,
I understood wat u hv done in the solution. big grin
But wat is the use of doing such a length calculation when we can filter the top three scorer in the 6th race.
Thanks,
Re: Numbers.
by TG Team - Wednesday, 1 August 2012, 02:52 PM
 

Hi Mohit smile

You can only judge top-scorer in the sixth race. You can't be sure of later position holder. Please think once more. smile