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Re: doubt of numbers
by harendra chaudhari - Monday, 23 July 2012, 10:33 AM
  a+b+c=23
let a=2p+1, b=2q+1, 2r+1
2p+2q+2r+3=23
2p+2q+2r=20
p+q+r=10
positive integral solutions=C(10,3)
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Re: doubt of numbers
by rakshit surana - Monday, 23 July 2012, 12:43 PM
  hi harendra, i think u did a lil mistake
since 2p +1 u have taken p will take all values including 0
p+q+r = 10
no of non negative solutions is C(n+r-1, r-1)
so C(10+3-1, 3-1)
C(12,2) which is equivalent to my previous solution
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