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Question of the Day
by raktim sengupta - Tuesday, 5 June 2012, 01:26 PM
 


Q1: X alone can do a piece of work in 15 days and Y alone can do it in 10 days. X and Y undertook to do it for Rs. 720. With the help of Z they finished it in 5 days. How much is paid to Z?
(a) Rs. 360 (b) Rs. 120 (c) Rs. 240 (d) Rs. 300

Q2: The sports association organized a 4000 meter race around a circular stadium having a circumference of 1000 meters, the fastest runner and the slowest runner reach the same point at the end of the 5th minute, for the first time after the start of the race. All the runners have the same staring point and each runner maintains a uniform speed throughout the race. If the fastest runner runs at twice the speed of the slowest runner, what is the time taken by the fastest runner to finish the race?
(a) 20 min (b) 15 min (c) 10 min (d) 5 min

Q3: If x = a2-bc, y = b2-ca, z = c2-ab, then what is the value of (a+b+c)(x+y+z) / (ax+by+cz) ?
(a) 3 (b) 2 (c) 1 (d) 0

Q4: Haina Island had a population of 300000 in the beginning of 1999. Its average growth rate is 4% per annum but due to tsunami at the end of 2001, its population reduced by 8% in that year. But it again maintained the 4% growth in the following years. What was the approximate population of the city at the end of 2003.
(a) 320646 (b) 346842 (c) 310462 (d) 322881

Q5: ABC is a isosceles triangle where AB = AC = 13 cm. I is the incentre of ABC such that AI = 7cm. Also BC = 20cm. Find ?ACB?
(a) 40' (b) 45' (c) 50' (d) Data insufficient

 

Please post the answers...with solutios off coursesmile

Re: Question of the Day
by raktim sengupta - Tuesday, 5 June 2012, 01:41 PM
 

soultion1- ans b)Rs 120

Let the work = 30 units(lcm of 15 and 10)

X's 1day work= 30/15=2units

Y's 1day work = 30/10=3 units

(x+y)'s 1day work = 3+ 2= 5 units

(x+y+z's) 1 day work= 30/5=6 units

z's 1 day work= 6-5 = 1 units

z wl take 30 units of work to do in 30 days

ratio of x:y:z=2:3:1 therefors z's share=(1/6)* 720= Rs 120...

Re: Question of the Day
by anuj kumar - Sunday, 10 June 2012, 04:12 PM
 

q2.. ans is 10 mins.

as the fastest is running at double speed of the slowest one..

hence when one round will be completed by slowest one the fastest one will complete two rounds..i.e at the end of 5 mins slowest one will cover one round while the fastest will cover two rounds..hence fastest will take 10 mins to cover four rounds.

Re: Question of the Day
by anuj kumar - Sunday, 10 June 2012, 04:18 PM
 

q4...

ans is c.

initial population=300000

@ the end of 2003=initial population*(1.04)*(.92)*(1.04)*(1.04)

                         =310462

Re: Question of the Day
by anuj kumar - Sunday, 10 June 2012, 04:26 PM
 

q3..

ans c-1

when u will solve the above eq it will be like

=(a+b+c)(a2+b2+c2-ab-bc-ca)/(a3+b3+c3-3abc)

as a3+b3+c3=(a+b+c)(a2+b2+c2-ab-bc-ca)+3abc

hence

=1