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Faulty Balance
by BlackZero . - Tuesday, 13 March 2012, 04:28 AM
  A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights. His total gain is ?


My approach:-
Dealer cheats 10% while buying. This means he is buying 1100 g for say 1000 Rs. He cheats by 10% while selling. This means he is selling 900g for 1000 Rs.
so, CP of 1100g = SP of 900g = 1000
CP of 1 g = 1000/1100, SP of 1 g = 1000/900
Profit = 1000/900 - 1000/1100 = 10/9 - 10/11 = 10*(1/9 - 1/11) = 10*2/(9*11) = 20/99
% P = ((20/99)/(10/11))*100 = 200/9 = 22.22%
But, the answer is 21%
Re: Faulty Balance
by santosh subramanya - Tuesday, 13 March 2012, 08:25 PM
  this is an easy question. let the actual price be 100 Rs. if he cheats while buying, then the faulty cost price becomes 110 Rs. now he keeps a profit of 10% to this. so he is selling at 121 Rs. so its a profit of 21% to the original which is nothing but the total gain. smile
Re: Faulty Balance
by Sanchit Sharma - Wednesday, 16 July 2014, 07:27 PM
  As per Arun Sharma for quant, (goods left/ goods sold)×100 will be the short cut. Which gives (200/900)×100.
So the answer should be 22.22% gain.
Re: Faulty Balance
by Shreyanshi Chaurasia - Thursday, 10 December 2015, 07:22 PM
  U can view it as 2 successive profits of 10% den using multiplyng factor 1.1*1.1 this will giv u 1.21 thus a profit of 21%