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Remainder problem
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Remainder problem
by
ketav sharma
 Monday, 19 September 2011, 02:00 PM
2^2001/2001 remainder ?
With solution
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Re: Remainder problem
by
sankar a
 Friday, 23 September 2011, 01:12 AM
2001=3*23*29
2^2001 mod 3 =2
2^2001 mod 23=12
2^2001 mod 29=14
Solve the following equations using Chinese Remainder Theorem
3x+2=23y+12=29z+14
we get N= 2001k + 449
Remainder is 449
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