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Re: Probability Problem
by R Maanav - Thursday, 29 September 2011, 10:51 PM

The year 1896 is a leap year. For the match boxes to have equal no. of match sticks after 31st december 2011, i.e. the 366th day, it is necessary that Lord Coin choose each match box equal no. of times.

Hence the ans. should be (366 C 183)*((1/2)^183)*((1/2)^183), i.e., (366 C 183)((1/2)^366))

irrespective of the initial no. of match sticks in each match box. What is the answer by the way?