
Z^N = 1
Value of z =1.
Explanation :
Since z > 0,
lets divide solution in steps :
1.Assuming z > 1,
z = 1+k (k = any value)
Z^N = (1+k)^N
that never be equals to 1.
2.Assuming z0)
this gives z <1 />
now ,
Z^N = (1/k)^K <1 that="" would="" be="" always="" less="" than="" />
3. Assuming z =1
Z^N = 1^N = 1
Hence, Z =1
