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HEXAGON problem
by any 203 - Thursday, 11 November 2010, 11:17 PM
  Q) A regular HEXAGON has a perimeter of 30 units.what is the sum of the length of all the diagonals?  

Re: HEXAGON problem
by shivam mehra - Friday, 12 November 2010, 02:30 PM
  regular hexagon let side be 'a'
6a=30
a=5

now 3 diagonals each of 2a units
hence 6a=30units
Re: HEXAGON problem
by Muhammad Saif Anwer - Saturday, 13 November 2010, 03:07 PM
  How is every diagonal equal to 2a. I mean all the diagonal can't b equal. Moreover v've got 6 more diagonals. Got it is the answer around 82.2?
Re: HEXAGON problem
by Muhammad Saif Anwer - Saturday, 13 November 2010, 03:29 PM
  There r 9 diagonals 3 big r equal to 2a each. The six small r root3* a. So sum= 6a + 6 rt3 a. = 30+30 rt3
Re: HEXAGON problem
by Amal Nicholas - Monday, 13 December 2010, 08:40 AM
  A regular hexagon has 3 diagonals (half the number of sides). Just like a square has 4 sides and two diagonals, because there are 2 pairs of diametrically opposite vertices. In a REGULAR hexagon, there are three pairs of diametrically opposite vertices. So there are 3 diagonals.
Now if u draw a regular hexagon, and draw all the diagonals, u will observe that the hexagon has been divided into 6 triangles. These triangles are equilateral triangles with side equal side of the hexagon.
So the length of one diagonal is 2a where "a" is the side of the hexagon. Therefore, the sum of the lengths of the diagonals is 6a=30.