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Average DS problem
by any 203 - Monday, 25 October 2010, 09:09 PM
  If the average (arithmetic mean) of the assessed values
of x houses is $212,000 and the average of the assessed
values of y other houses is $194,000, what is the average
of the assessed values of the x+y houses?
(1) x+y=36
(2) x=2y

kindly explain the correct answer,,,,
Re: Average DS problem
by Gaurav Verma - Monday, 25 October 2010, 10:12 PM
  both the conditions are alone sufficient for finding the average ....
Re: Average DS problem
by Abhirup DebRay - Monday, 25 October 2010, 11:46 PM
  the desired average will be = (212,000 x + 194,000 y)/(x+y)
now statement 1
x+y=36 This will get the value of the denominator but there will be a variable remaining in the numerator. So INSUFFICIENT
now statement 2
x=2y If this is substituted in the desired average then the variables will cancel out each other & we will get a unique value . So SUFFICIENT
Hope it helps
Regards
Abhirup
Re: Average DS problem
by any 203 - Tuesday, 26 October 2010, 11:28 PM
  the original answer as given in set is  'C' ,,,,
Re: Average DS problem
by any 203 - Tuesday, 26 October 2010, 11:31 PM
  Hi, Gaurav ,
kindly elaborate how  to arrive at  'C' 
Re: Average DS problem
by Govi Ravi - Thursday, 18 November 2010, 11:22 PM
 

X * A1 + Y * A2 / ( X+Y)

 

A1 & A2 are given in the stem.

 

Combining st1 & st2 we have the values of (X+Y), X, Y. Put them back in the weighted average equation.