Re: square problem | |

Hi Kamal \ TG, can u throw some light on this problem ,,,,, |

minimum Value | |

If x,y,z are any integers and x+y+z = 3 Find the minimum value of (1/x)+(1/y)+(1/z) a) 3 b)-3 c)-9/5 d)-4/3 |

integral solution. | |

find positive integral solutions of 15x + 4y + 19z = 140 . |

Re: minimum Value | |

This question is for any value of x , y , z not positive value of x,y,z |

Re: square problem | |

answer as given in solution for square problem is C ,, that is 33.75 ,, unable to figure out how ,,, may be it is wrong answer ,,,,, |

Re: square problem | |

Considering the least possible value as 5.5, the area would be 30.25. Rounding up 5.4 to the nearest value will result in 5. So it must me at least 5.5 to round to 6. |