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Re: Probability
by ashish sharma - Sunday, 7 February 2016, 06:19 PM
  In addition one more query in the example of dice thrown 10 times and probability of it showing "six" exactly 3 times?

If I go by conventional method, total outcomes= 6^10
Favorable outcomes= 10!/(3!X7!)
However, as solved by you the probability is way higher than above. So, where exactly I am missing additional favorable cases?
Please clarify