d] 166.67 m
5] X set out at 12 noon to walk from Borivali to Bandra & a friend of him Y started at 2 pm on the same day to walk from Bandra to Borivali by the same road. They met on the road at 5 mins past 4 & both of them reach their destination at exactly the same time. At what time did they both reach their destination ?
b] 6 pm
c] 7 pm
d] 8 pm
explain ur answers in detail
1) Let 'n' be no.of boxex then speed of cart is given by |
speed=18-a*root(n) where a is const.
from given data speed=12 when n=9 ; we get a=2.
hence equation is speed=18-2*root(n)
thus for speed=10kmph we get n=16
hence total weight of cart=16*10=160 kg
squaring gigen eq. m^2/n^2=p^2/q^2=a^2/b^2=1/9
by slight modification 2m^2/2n^2=p^2/q^2=3a^2/3b^2=1/9
by using ratio pro. rule(ie. if a/b=c/d then a/b=a+c/b+d=c/d)
we get ans. as 1/9
1 n 3 r replied...|
rest ans are: 2 - b, 4 - d, 5 - c
Q 4 is straight frwrd....say Rajesh has a start of 'x' meters, so he has to cover '1000-x' m's. Both finish at the same time, hence:
(1000-x)/10 = 1000/12, solve now for 'x'...simple!
Q 2 is a simple logic based...
say 2x,3x,4x are initial investments
So after some months, A becomes 2x-x = x
and C becomes 4x-x = 3x, B remains the same.
So profit ratios which are 2:4:5 depend on the time for which the money was put by the investors.
So, we can say profits are 2y,4y,5y
Suppose B had points 12*3=36 points, he invested his money for all 12 months and had a ratio '3'.
Now profit is 2:4:5, so A must have 18 points, since we gave B 36!!
Simple thinking shows if A takes half the money after 6 months, then he has 6*2 + 6*1 = 18 points.
So, 2:4:5 and 18:36:?, ? will be 45 ;)
now simple trial and error....C takes out money after 9 mnths...hence his points become 9*4 + 3*3 = 45...hence is the answer.
Simple funda....profits will be in the ratio of the investments only
Q 5....its also simple....though a lil hectic calculation based!
aah cant write it all here...try it again...its a very old thread btw....u must have figured it out....if still u havent....mail me!!
|hey can you make question 3 more explanatory as its difficult to understand in such a manner|
Hi Tamseel Najmi |
Let n = 3m, q = 3p and b = 3a, so given fraction becomes:
(2m² + p² + 3a²)/(2n² + q² + 3b²) = (2m² + p² + 3a²)/(18m² + 9p² + 27a²) = 1/9.
Hope this is clear.