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You are here,
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 | Re: How to find last two digits of a number |
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For: last two digits of 14^14^14?? -> 14^14^14 = 14^(2*7)^14 consider (2*7)^14 => 2^14 * 7^14 => 2^10 * 2^4 * (7^4)^3 * 7^2 => __24 * 16 * __01^3 * 49 => __16 Therefore 14^14^14 => 14^__16 => 2^__16 * 7^__16 => (2^10)^odd no * 2^6 * (7^4)^4k => __76 * 64 * (__01)^4k => 64
why am i getting 64? Is it correct? |
 | Re: How to find last two digits of a number |
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Hi Rhythm Goyal Everything was fine except second-last step where it should be 24 in place of 76 and the answer will be 36. |
| Re: How to find last two digits of a number |
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Oh... Thats so stupid of me... I have verified my calcluations thrice before posting. Still got same wrong answer all the 3 times. Thanks a lot Sir. I may now not comitt such in CAT. Sir, I need to discuss regarding Regular batch / CBT. Where can we discuss? |
