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Re: Number System- 2: Remainders
by Devashish Acharya - Sunday, 30 August 2015, 07:33 PM
  Ans is 1

Solution:
By Fermat's Little Theoram:

a^(p-1) - 1 = kp ( where k is a constant & p is prime number)
and a & p co-prime.

a = 17, p = 37

17^(37-1) - 1 = 37k
=> 17^36 = 37k + 1

Hence, Remainder = 1