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Number System 2: Remainders
Re: Number System 2: Remainders
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Re: Number System 2: Remainders
by
Devashish Acharya
 Sunday, 30 August 2015, 07:33 PM
Ans is 1
Solution:
By Fermat's Little Theoram:
a^(p1)  1 = kp ( where k is a constant & p is prime number)
and a & p coprime.
a = 17, p = 37
17^(371)  1 = 37k
=> 17^36 = 37k + 1
Hence, Remainder = 1
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