Permu n Combi  I  
Frns, Lets solve all the Permutation n Combinations problems given by TG in Lessons Section  10 a Day... What Say ! VaMsI here are the first Ten : 
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Answers are : 1. 32 2. 900 3. 60 4. ***** 5. 17999 6. 36 7. 3 8. 4 9. 2 10. 256 kindly let me know the correct answers . Thanks Tuhin

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Tuhin 4. Am gettin 26^3 . 220 7. donno.... 
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Sorry the last one was the answer of question number 6. 
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The answer of q.4 is 26^3*220 only. I am getting the same answer. 
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Hey Can Sumone Throw sum light on PROB 4 n 7? 
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hi vamsi , BRBGR <>BRGBR & RGRBG<>GRGRB become identical....pls put them on the fig of regular pentagon.

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itz Hard 2 digest Thanks Bimal... 
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Consoliated Answers: 1. 32 2. 900 3. 60 4. 26^3 * 220 5. 17999 6. 36 7. 3 8. 4 9. 2 10 256 VaMsI 
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Here goes the next ten, Post ur ans only... we'll compare our answers and discuss da insane ones VaMsI 
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Catender, Q19) In the expansion of (a1 + a2 + a3 +.......... + ar)^n there are C(n+r1,r1) terms Try for small values of r and n VaMsI 
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Thanks Vamsi, u took me to the good old days of IIT preparation.. 
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Could not get the steps for 10th one. Please post it. Thanks Bishweshwar 
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vamsi/ anybody please explain the question number 4 !!!!!!! its getting OVER HEAD TRANSMISSION Regards Sunil Garg 
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Hi Sunil, 4 or 14? VaMsI 
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PLEASE PROVIDE SOME HINTS OR APPROACH TO ALL QUESTIONS AS WELL 
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11) 2240 12)50 13)35 15)35 16)12 17) 168 18) 9 19)136 20)315

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HEY Tuhin watz ur approach for 13th VaMsI 
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hi vamsi yaar please explain the qn number 4 and pentagon wala qn regards sunil garg 
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ANSWER OF QN 14 IS ............'S '......For Sunil 
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Guyz, 14) 'T' VaMsI 
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thanx vamsi for question number 4!!!! what about pentagon question regards' sunil 
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@ bishweshwar 10) there are 2 ways to move around each circle 8 adjacent circles implies 2^8 = 256 ways VaMsI 
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Next ten Sir? Regards Avi 
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11 A 12B 13B 14B 15A 16B 17C 18D 19Don't know 20C ...RK... 
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Question In how many ways can one or more of 5 letters be posted into 4 email boxes, if any letter can be posted into any of the boxes? 15^{4}24^{5} 35^{5} 1 44^{5} 1 ...RK... 
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each letter can be handled in 5 ways . Either post it in one of the 4 email boexs or do not post it . So ans option 4  4^51 
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Ambar, In that case the answer should be 5^{5}1....and that's the answer indeed! Thanks ...RK... 
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lolz ... yes !! 
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Nice explanation , Bro !! gaat it . 
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Thanks Amber Hey any Takers for Q13 n Q14? VaMsI 
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hey Vamsi how would you get 220 in Q4. rgds/Amit 
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Hi Amitji I hav already posted my solution. jst scroll down furthr. VaMsI 
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hey rishi how come 5^{5}1 .. it should be 5^{4}1...
Amit 
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Thnx vamsi.. i got the solution for q4. could you pls tell me how to solve Q6. Amit 
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amit Same reply again jst scroll down... Check da solution given for Q19 VaMsI 
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hmm..Sunil.. 15)Jst scroll down sumwhere i hav discussed. 18) disarangement formula (Thanks 2 TG sir) Source: Wat else...TG site at da end of this lesson http://totalgadha.com/mod/forum/discuss.php?d=3537 VaMsI 
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Q13 Take the four people out.We are left with 6 people and 7 places to fit in those 4 asses.This can be done in 7_{C4} ways = 35 
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@ avi Again am lost @ Catendra Hey Gr8 solution Bro Thks VaMsI 
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Consolidated Ans for SETII 11.2240 12.50 13.35 14.T 15.35 16.20 17.240 18.9 19.136 20.315 VaMsI 
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N da next Set is here... Am sure "avi" is eagerly lurking around for this set VaMsI 
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1. 204 2. 32 3. 35,120, 10(4!) 4. 26!/2 5. 45, 21, 35 will do the rest later. Regards Avi 
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26 4^{5} 2711804750000 ???? ...RK... 
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ah ... i see . what a trap ! 
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Hi Vamsi, Sorry being late, approach for the 13th no. same as Bimal mentioned. 
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21)204 22)32 23)840/120 24)26!/2 25)45/21/35 26)56 27)11804750000 30)19 Bimal

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nitin Scrolldown further, i hav mentioned my approach for Q4. VaMsI 
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480 VaMsI 
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Thanks Vamsi, the approach is perfect... Cheers Partha 
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hi pl expalain explain q no28,29&30 in detail can somone explain the approach behind (cube & colour) questions. 
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could u plz explain how u get answr to question no. 05 
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Hey please provide explanation key for all the questions. 
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someone please provide explanation key for all the questions 
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While considering case b in the solution to the question 4 above, haven't we already taken greater than preceding no. in case (a)?? 
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i'm getting answer of 9th question 3... plz clarify it.. 
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Hi all,
Need the explanation for this question:
(a+2b+3c5d+4ef2g7h)^2 . Number of terms in this? 
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hi need the solution for q17.... i am doing some stupid mistake and need to know where am i going wrong thanks 
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I'm getting it as 240 (5C2 * 4!) Please let me know your approach. 
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Hi vamsi krishna, this is bhanu...i'm about to give CAT this year... your way of approach to the problems were really good.. thanks a lot 
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can u please explain me the method to solve ques number 10...that is of 8 circles... 
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n0  18 This is an dearrangment question 4!(1/2!1/3!+1/4!) = 9 
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HEY, can some one pl;s explain Q.17? the 3digit number one... thanx. 