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 | Re: Permutation and Combination |
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in the question of multiple choice test with 5 choices, i think there are 6 possible ways of answering the questions instead of 5 as a person can also leave the question/s unanswered which i think is the 6th way of doing a question. therefore solution will be... 6^30 but i am not sure, so please let me confirm that my approach is correct or not..  |
| Re: Permutation and Combination |
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Great article...thanks a ton TG...your articles motivate to study more as concepts seems to be so simple.... I have a question , if you or anyone can help me out... In how many ways 25 balls can be selected out of 15 identical red balls,20 identical blue balls and 25 identical green balls ? My Approach : consider 3 persons A,B,C to whom I have to distribute these balls.So, I distribute all balls , say 15 Red to A , 20 Blue to B and 25 Green to C .Total =60 . Now I can take out 35 out of them as we want only 25 balls in total. so, finding solution of equation x+y+z= 35 should give answer . But my answer coming wrong. Correct answer is 281. Can anyone tell me where I am going wrong.  |
