Number System Problem  
1)What is total number of Zero at the end of (625!)!. 2)What is the total number of digits of 1!+2!+3!+.......+98!+99!+100! 3)Last Two digits of 8^7^6^5^4^3^2.

Re: Number System Problem  
3.36...... 
Re: Number System Problem  
But how? Please explain in detail.

Re: Number System Problem  
sorry i made a mistke in solvn...... not the answer... ... i think ...... 08..... but pehle plzzz say rite or not...then i'llpost my soln.. 
Re: Number System Problem  
no in such kind of ques u just have to find no of 5 in 625! for that jus keep on dividing by 5... like 625/5 = 125 125/5 =25 25/5 =5 5/5 = 1 now the ans is 125+25+5+1=156 
Re: Number System Problem  
156 is alryt..but that is only for single factorial ,wat about d other one.. i think it will be.. 194... correct me if m wrng 
Re: Number System Problem  
last two digits will be 28 following general method of cyclicity. need to dig up for 2nd one.. 
Re: Number System Problem  
How to proceed in the 2nd que? 
Re: Number System Problem  
kamal, Is this approximation applied to find the number of digits of 100! or the number of digits in the sum of 1!+2!+...100!. 
Re: Number System Problem  
kamal sir ,we are waiting for your answer to 3rd ques....plzz help us out 
Re: Number System Problem  
156 zeros 