New Batches at TathaGat Delhi & Noida!               Directions to CP centre
DI Challenge for CAT 2008 Aspirants
by pradeep pandey - Thursday, 6 March 2008, 04:37 AM
 

cat 2008 cat 2009 preparation mba 2008 xat 2008As promised to us, Mr. P. Pandey is posting his Data Interpretation challenge for all CAT 2008 aspirants on TG. If other instructors in the field can also come forward and share their wealth of knowledge on TG, education will come alive in millions of hearts. Till that happens, we will keep going on our own, with a little help from friends. So all you CAT 2008 daredevils out there, you are invited to a duel with this DI challenge which is, in Mr. Pandey’s own words, ‘the Litmus test of their arithmetic skills particularly in time & work, and average’. If you are able to solve these questions, you can consider yourself an expert in these topics.

Funny how a long time has passed since I took my CAT paper but the excitement on seeing a new question still remains the same. Most of you students take these questions with a dread. Unfortunately, you miss the fun and excitement of CAT preparations, the warm feeling of contentment on cracking a question, the ego-trip of getting problems right. In order to be good at anything in life, you need to start loving it. And once you start loving something, you start loving yourself when you become good at it. That’s life.


DI Challenge for CAT 2008


Re: DI Challenge for CAT 2008 Aspirants
by PRIYANKA KESHRI - Thursday, 6 March 2008, 02:27 PM
 

hi!!!!

tried a few ... got my ans as...

1)5               7)1

2)1                 8)??

3)3               9)4

4)?                10)5   

5)3

6)4

Re: DI Challenge for CAT 2008 Aspirants
by Pyara gadha - Thursday, 6 March 2008, 02:55 PM
 

Solvd the First Set

1. Sum of top scores= 435

Sm of minimum scores=153

To find the maximum avg we have to maximize the other scores, for that the 6th top score should be highest so that rest can just preceed it.

Avg of top 6 scores 72.5 So to make 6ht highest score maximum the scores have to be 70 71 72 73 74 75

Now if we chose 16 nxt scores from 69 68 ... 54 Sum of these scores= 984

Two scores are 48 49 sum= 97

So total sum= 1669

Hence maximum avg = 55.6 (1)

2. Avg.=45.2

so total runs scored= 1356 minus the 6 highest scores(435) nd 48 49 scored by him we get runs the total of rest of scores to be 824

Now if we assume n fifties scored by him

Let the scores in fifties be 50 51 52 .. (n elements) (1)

Other scores b 0 1 2 3 ... (30-6-2-n elements) (2)

so summation of 1 & 2 we should get a score close to 824

By this we get n=14

Plus the 6 highest scores which all could be fifties

We get Total no. of Maximum Fifties=20 (4)

3. Let the two centuries be 100,101

So Total score scored in his next 4 highest scores = 435-201= 234

Again to maximize the lowest score the 6th highest score should be maximum So the nxt top scores would be 57 58 59 60

6th highest is 57 rest can follow like nxt being 56 55 54 nd so on 

The 30th score comes to be 33

So maximum highest lowest score would be 32 (3)

4. To maximize the highest score we have to minimize the rest of the top 5 scores

Now Sum of lowest 5 scores=153 We have to hav minimum 5th lowest score

so that rest of scores can follow it

So the minimm possible fifth lowest score is 33

nxt scores can follow as 34 35 36 nd so on till 2nd highest score = 57

So sum of 2nd highest score to 6th highest score= 57 + 56 ... + 53= 275

Highest score= 435-275= 160 ( Didnt find any option)

5. Again we have to find the highest 6th score= 70 so that rest of the scores can follow

By this we get highest scores as 70 71 72 73 74 75

Now if we try to increse the highest score we have to decrease atleast 1 from all the scores(-29 from total score) which would result in increase of only 5 in the highest score because sum of highest six scores also will have to be constant

So maximum highest score in this condition is 75 (1)

 

 

 

 

 

Re: DI Challenge for CAT 2008 Aspirants
by grv .. - Thursday, 6 March 2008, 06:41 PM
  My attempt for 2nd set:
6) 4
7) 2
8) ???
9) 4
10) 1
Re: DI Challenge for CAT 2008 Aspirants
by Pyara gadha - Thursday, 6 March 2008, 07:01 PM
 

2nd Set

1. Efficiencies of Men

A: 1200*4/5= 960

B: 1600

C: 800*5/7= 571.43

D: 2000*5/3= 3333.33

E: 2800*5/7 = 2000

So correct order DEBAC (4)

2. Efficiencies of Women

A: 960*2/3

B: 1600*4/5

C: 4000/7*1/2

D: 10000/3*3/4

E: 2000*3/5

So most efficient women is with D or Rampur (2)

3. no. of days taken for girl of tolly if girl from murali takes 100 days

= 100*(3/2)*(4/3)*(2/3)*(960/(4000/7))*(2/1)*(3/2)*(4/3)

= 896 days (2)

4. Efficiencies of girls

A: 960*2/3*4/3*3/2 = 1280

B: 1600*4/5*3/2*5/4 = 2400

C: 4000/7*1/2*2/3*3/4 = 1000/7

D: 10000/3*3/4*5/4*2/5 = 1250

E: 2000*3/5*5/2*3/4 = 2250

So least efficient girl is from Tollyganj (5)

5. (10000/3 - 2000)/2000*100= 66.67

So it is 166.67% of 2nd most efficient one (1)

 

Re: DI Challenge for CAT 2008 Aspirants
by Manash Saikia - Saturday, 8 March 2008, 05:59 PM
  Hi Pradeep,
   Indeed a great article!! These questions are of the same level  as the real CAT.
   I am able to solve very few questions. So verify plz post a solution to all these questions in detail.Also plz give some tips to solve similar type of questions.
   Waiting for the solutions!!

Thanks !!
Re: DI Challenge for CAT 2008 Aspirants
by bimal mohan - Sunday, 9 March 2008, 01:01 PM
 

hi   pg  ,

    good   solution....

  but  i  think   in  4th  ques:  (  1st  set  )

    153= 35+31+30+29+28   ,  so  

So the minimm possible fifth lowest score is 35,   ultimately   resulting  a  answer  =150....in  this  case  too   ,  does  not  match  with   the  options  !!!

Re: DI Challenge for CAT 2008 Aspirants
by Pyara gadha - Sunday, 9 March 2008, 02:36 PM
 

hi bimal,

33+ 32+31+30+27 or 33+32+31+29+28 can be values to attain 33 as minimum possible scores

Re: DI Challenge for CAT 2008 Aspirants
by bimal mohan - Sunday, 9 March 2008, 03:13 PM
  yes  pg  ....u  r   right  ....by  the  way  , how  did  u   solve  the  2 nd  set  ? 
Re: DI Challenge for CAT 2008 Aspirants
by Pyara gadha - Sunday, 9 March 2008, 03:21 PM
 

Least efficient man from chart we can see to be C

Its given that to do that work least efficient man increses his original efficiency by 40%

So if his efficiency is x then 140%of x is 800

or x is 800*5/7

So on so forth

Re: DI Challenge for CAT 2008 Aspirants
by rohit miglani - Sunday, 9 March 2008, 05:02 PM
  hi pg,
   Nice solutions but can you explain them little more. in 1st set  2nd one and do tell me how to improve my DI skills.
Thanks 
Re: DI Challenge for CAT 2008 Aspirants
by nirmesh sinha - Monday, 10 March 2008, 03:17 PM
 

11. 1

12. 2

13. 4

14. 4

15. ?

Re: DI Challenge for CAT 2008 Aspirants
by brendan decruz - Tuesday, 11 March 2008, 09:06 PM
 

hi dude,

if i am not wrong i think these questions were also given in one of the issues of "CATS EYE"....i don remember which month issue though.... just that they all seemed so familiar!!!!

 

Re: DI Challenge for CAT 2008 Aspirants
by psp psp - Monday, 17 March 2008, 10:43 PM
 

In the second set

after the ratios A. (9:6:8:12) B.(10:8:12:15) C.(12:6:4:3) D.(16:12:15:6) E.(40:24:60:45)..pls tell me how is it found out that man in C has least efficiency..

 

Re: DI Challenge for CAT 2008 Aspirants
by Soumya Kanti Banerjee - Wednesday, 19 March 2008, 03:16 PM
 

NICE QUESTIONS.........my answers for first set are

1.1

2.2

3.4

4.2

5.1

Which r the right answers?

 

Re: DI Challenge for CAT 2008 Aspirants
by Aijaz Ahmed - Wednesday, 26 March 2008, 12:31 AM
  hi...the logic is right in 1 ques but i think that we will have to take no from 69 to 52(18 nos) sum=1089

as 48 and 49 can be the part of his min 6 scores as well. for eg:-his min scores can be 49+48+a+b+C+D=153  (a,b,c,d can b assidned diff values as there is no restriction)
so max total runs=1089+153+435=1677
and so max avg will be 55.9
Re: DI Challenge for CAT 2008 Aspirants
by jupiter singh - Wednesday, 26 March 2008, 07:46 PM
  dude let me knw if im wrong adding 435+429....comes to 2114 dividing uget 70.44 ucan add upto 24 but due unavailability of option uget only 17 to add then ucanadjust rest toget the same result without dissatisfying conditions...
Re: DI Challenge for CAT 2008 Aspirants
by pradeep pandey - Thursday, 27 March 2008, 06:53 PM
  Hi All,

Here are the answers to the DI challenge.

Total Gadha
Re: DI Challenge for CAT 2008 Aspirants
by Lord Aragorn - Monday, 28 April 2008, 09:23 PM
  Hi in the cricket zone problem.
Question no 3:

The scores must be taken as 101 and 100 and after these two the rest of the
scores must be taken such as to maximize the lowest i mean the 6th highest score so that the minimum score i.e 30th can be maximized.

So why didnt we take the scores as 101, 100, 60,59,58,57  summation of these is
435 so condition satisfied. next the lowest scores will be 56, 55,54 ......24th = 56-24 +1 = 33 . the two score of 48 and 49 are also there in these so that constraint also met...
please clarify and point out my mistake...
Re: DI Challenge for CAT 2008 Aspirants
by Lord Aragorn - Monday, 28 April 2008, 09:35 PM
  The question 4: says 5 min scores and th esolution says 6.
I solved for what the question mentions.
the 5 lowest scores came out to be 33,32,31,30,27  so the 6th is 34 and the 24th is 52. hence the lowest amongst the top 6 are 53+54+55+56+57 = 275. so highest is 435 - 275 = 160

is this correct
Re: DI Challenge for CAT 2008 Aspirants
by Abhinav Rawat - Thursday, 11 September 2008, 11:06 PM
  HI, how  did you arrive at the conclusion for the 2nd question that , other scores b ..0,1,2,3  ...
you have not taken ino consideration the fact that , his total for lowest 6 scores is 153..