Re: Mensuration Solids  
Another Nice Stuff to go through. Expecting the saga to be continued in future. 
Re: Mensuration Solids  
HI!!! HEY IT'S A BEAUTIFUL ARTICLE... NO DOUBT VERY USEFUL FOR ALL CAT ASPIRANTS... WONDERING HOW COULD U BE SO CREATIVE!!!!!!!!! 
Re: Mensuration Solids  
4th ans=O option(d) Little Star 
Re: Mensuration Solids  
TG is on total rampage !! It is adding killer material day by day ...... Hats off to TG .... 
Re: Mensuration Solids  
4  d 5  A 6  c ..... but took me too long to come to the final answer . 7  d 
Re: Mensuration Solids  
2 ) can be 9 / sqrt(2) .... not sure though 
Re: Mensuration Solids  
dude isnt the awnser of 4 cmidpoint and awnser if 5 ithink is d 
Re: Mensuration Solids  
V.Good 
Re: Mensuration Solids  
TG , throw some hints for the rest of the problems ..... 
Re: Mensuration Solids  
Hi Ambar, Will post solutions in a day or two. Total Gadha 
Re: Mensuration Solids  
1...17.77 min 2...5*a*a/4 3....288*pi 4....A 5....A 6.....C........4CYL:::::::::::;3CYL+3CONE:::::::::::;;2CYL+2CONE+1SPHERE 7....c 8....c 9.....240*pi(but not sure) 
Re: Mensuration Solids  
yep , the answer to 3 is 288pi similarity of triangles is the key 
Re: Mensuration Solids  
2. a/(2*sqrt(2)) not sure of the answer. 
Re: Mensuration Solids  
psp psp , I think it shud be a^{2}/ ( 2 * sqrt(2) ) 
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yes its a^{2} /(2*sqrt(2)) thanks. 
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9 ) (4/3)*pi*6^{3 } (1/3)*pi*3^{2}*5 =273*pi .. pls show where i am going wrong 
Re: Mensuration Solids  
Hi all, My answers are: 1  17.77 min 2  ((6^{0.5} +1)/ (2*2^{.5})) a^{2 }3  4/3 pi (48/7)^{3 4  A 5  A 6  C 7  C 8  C 9  240 pi}^{ } 
Re: Mensuration Solids  
great article TG... 
Re: Mensuration Solids  
Great TG Sir. Could you please post some lessons on the very basics of 'Functions'. This chapter really troubles me. Thanks

Re: Mensuration Solids  
echo joel , Sir we are waiting for your articles on Functions and Graphs . Thenks . 
Re: Mensuration Solids  
pls. disclose answer key with detailed solutions. 
Re: Mensuration Solids  
hi tg
awesome
but pls post the answers soon....
regards catmania 
Re: Mensuration Solids  
Ya i agree with you manash.......42.222 is the right answer for question #1 
Re: Mensuration Solids  
sorry my answer to question no1 was wrong its 17.77min 
Re: Mensuration Solids  
The answer to Q1 is 42.22 mins. 
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Can someone please help me with the steps for Q3 & Q9 ?? Regards, 
Re: Mensuration Solids  
Answer no 9) 240pi+9sqrt(2) pi=252.69 pi The volume of the remaining portion would be vloume of the Sphere(remaining part)+volume of the cone( coz that part is not used too)

Re: Mensuration Solids  
yep..i also got the answer to question number 1 as (19/27) * 60 which is approx 42.2mn.. 
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Dear Sir, It would be immensely helpful if you could post the solutions to all the problems you have given in this article. Thanking you, Monika 
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Can you please post the solutions? 
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HI my answers are 3. 288pi 4.d 5.125pi/sqrt3 6. c 7. c. 9.240pi 
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Ans pls.. 
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TG, Isn't the curved area for a frustum (pi)(Rr)l ? [ As cone's curved area is (pi)rl ] Thanks, 
Re: Mensuration Solids  
Hi TG and all, Please explain the solution for the Q9. Is it solved with some concept of steradians? Thanx in advance 
Re: Mensuration Solids  
Hi AK, the 'l' (slant height) is not the same in the two cones if I am guessing right what you are thinking. Total Gadha 
Re: Mensuration Solids  
oops...it seems I have goofed up with my concepts. Yes, I misinterpreted the 'l.' 
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Hi TG Can you please explain the first question????????? 
Re: Mensuration Solids  
Hi TG Can you please explain the first question????????? 
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TG we are not getting replies too often from ur side???????
Hop u r not busy with classes 
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7: (c)102 8: (c) 9: (1289âˆš3)Ï€ 
Re: hey TG!!!  
sir, please post the solutions 
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the correct answers?? 
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Hi TG, Answers please.... 
Re: hey TG!!!  
just try continuously in building ur basics u will be easily able to do it 
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TG Sir , Where I can find the solutions to above questions ? 
Re: Mensuration Solids  
Sir can u provide pdf on each quant lessons... Pls sir, thanks in advance... 