Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
hi tg atleast tell which questions i have done wrong 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi Bharat, Try question 3 and 8 again. Total Gadha 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Answer for Q 10 6*(3*3) + 6* (1*1) = 78 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
ans 3 is it (2^4)*(3^2)*5=720 30 factors 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
ummm..try more? One hint If I remember correct, the answers to question numbers 3 and 8 are the same..not sure though 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
i'll not bore u further, my last try 2^3*3*5*7=840 32 factors is it right...........

Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
hi tg ....... i am not able to understand the 5th question ie what it is asking.......and what is the ans of question 8......... 
Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi all, just tried out the remainder problem and got the answer similar to bharat.My approach is as follows: Remainder of 19^92 / 92 Soln1: 19^92 / 92 = 19^92 / (4 * 23) we can write this as (19^92 / 23 ) * (1/4) taking 1/4 out Simplifying this again we get (19^22 / 23 )*(19^22 / 23 )*(19^22 / 23 )*(19^22 / 23 )*(19^4 / 23)*(1/4) Now applying Fermat's Little Theorem...which states if p is a prime and a is an integer coprime to p, then Applying to the above expression (19^22 / 23 ) results in 1. We are left with (19^4 / 23)*(1/4)... This can be written as ( 361^2)/92 i.e ( 7^2)/92 i.e 49 I have also solved it by using Eulers Theorem which is easier than this method....Try it... 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
23/128 ..small correction 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Good work Swastik and Kiran 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
yes sir u know better than i/me Eagerly waiting for ur next article............ 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
hi tg Remainder of 19^92 / 92
i have a doubt in this method that how can we break the denominator .......... for eg 23/10 remainder is 3 now if i break the remainder into 5*2 then 1/5*(23/2)=1/5 remainder will be1 if this is the case in above method then why did the ans came same.......

Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
hi tg my ans to 5th problem is 93/512 (1+8+28+56)/512=93/512 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi Chinni, TG is alive 24 hours. There is no night and day on the internet. Total Gadha 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi Sandeep, Try solving questions 1, 4, and 8 once again. Good solution to question 6. Total Gadha 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi Vaseem, 8:00 pm is correct. See Sandeep's explanation also for Question no. 6. Total Gadha 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Let me think once again...... 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
10) answer is 72 unit square (91)*6 for cube external surface (1*1*1*1)*6 for internal open cubes 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi, Can you provide me the Correct answer and Solution to Q.5 ? 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi TG, I am getting answer for Q. 5 as '107/256'. (probability of no. of 0's greater than no. of 1's.) Is it correct?? 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Hi TG Sir, No new solutions............. No new doubts............
ab tho correct solutions bata do......... 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
can u tell me how did u solved this as i m not understanding ur method 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
answer 4114 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Q.No 6 8PM 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Ans for Q No 10: Total initial surface area = 6*9 = 54 After cut = 54  1*6 + 5*6 = 78 Ans = 78 There are five small surfaces in the groove. 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
Q.1 The number of NxN will have Colors = N + (N1)/2
Put n = 1 you get only one color Put n = 3 get 4 color (see inner cubes of 3 size) 
Q:6  
Time in city X will be 7 PM 
Re: Q:1  
qn 1. (n+1)/2 +(n1)/2+(n3)/2 + ..........(n(n2))/2 = n+1 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
I got the same answer for question no 5. Answer should be 65/256 only. 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
ans 3: (2^3)*3*5*7=840 the number of factors is 32 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
1) Sum of natural numbers till (n+1)/2 2) 3 3) 840; 32 divisors 4) 114 5) 130/512 6) 8:00 Pm 7) 49500ml 8) 420 9) 28 10) 72 Sq.m 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
For 2nd Question, answer is 49 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
hi friends plz explain me the 1st question about how colours are pattern acording to symmetry cudnt discern it. 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
in q8 n is three digit number or not??? without mentioning number of digits we can't i think 
Re: Total Gadha's Quant Challenge for CAT 2007 Aspirants  
sir ...the number having highest number of factors will be 840 